Evaluate the following limit:
limt→1−t2−|t−1|−1|t−1|.
1
2020-05-26T20:01:23-0400
t→1lim(−∣t−1∣t2−∣t−1∣−1)
t→1+lim(−∣t−1∣t2−∣t−1∣−1)=t→1+lim(−t−1t2−t+1−1)=
=t→1+lim(−t−1t(t−1))=−t→1+limt=−1
t→1−lim(−∣t−1∣t2−∣t−1∣−1)=t→1−lim(t−1t2+t−1−1)=
=t→1−limt−1(t+2)(t−1)=t→1−lim(t+2)=3
t→1+lim(−∣t−1∣t2−∣t−1∣−1)=−1=3=t→1−lim(−∣t−1∣t2−∣t−1∣−1) Therefore
t→1lim(−∣t−1∣t2−∣t−1∣−1) does not exist.
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