Find first fx and fy
fx=∂x∂(ex+ysinx+9x2+2xy)=ex+ycosx+18x+2y, fy=∂y∂(ex+ysinx+9x2+2xy)=sinx+2x.
To find fxy and fyx, take the partial derivative of fx with respect to y and fy with respect to x, respectively.
fxy=∂y∂(ex+ycosx+18x+2y)=cosx+2,
fyx=∂x∂(sinx+2x)=cosx+2.
Then,
fxy(1,2)=fyx(1,2)=cos1+2.
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