∫(x2+4xy)dx
=∫x2dx+∫4xydx [ ∵∫(f(x)+g(x))dx=∫f(x)dx+∫g(x)dx ( Where f(x) and g(x) both are functions ) ]
=∫x2dx+4y∫xdx [ ∵∫cf(x)dx=c∫f(x)dx ( Where c is a constant and f(x) is a function ) ]
=3x3+2yx2+C [ ∵∫xndx=n+1xn+1+C ( Where C is a constant of integration) ]
Comments