Question #108097

∫(x² + 4xy) dx


1
Expert's answer
2020-04-13T19:13:41-0400

(x2+4xy)dx\int (x^2 + 4xy) \, dx

=x2dx+4xydx= \int x^2 \, dx + \int 4xy \, dx \hspace{1 cm} [ (f(x)+g(x))dx=f(x)dx+g(x)dx\because \int (f(x) + g(x)) \, dx = \int f(x) \, dx + \int g(x) \, dx \,\, ( Where f(x) and g(x)f(x) \text{ and } g(x) both are functions ) ]

=x2dx+4yxdx= \int x^2 \, dx + 4y \int x \, dx \hspace{1 cm} [ cf(x)dx=cf(x)dx\because \int cf(x) \, dx = c \int f(x) \, dx \,\, ( Where cc is a constant and f(x)f(x) is a function ) ]

=x33+2yx2+C= \frac{x^3}{3} + 2yx^2 + C \hspace{1 cm} [ xndx=xn+1n+1+C\because \int x^n \, dx = \frac{x^{n+1}}{n+1} + C \,\, ( Where CC is a constant of integration) ]


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