Question #108090

∫ (secxy + siny²) dx


1
Expert's answer
2020-04-13T19:37:51-0400

sec(xy)dx+siny2dx=1ylog(sec(xy)+tan(xy))+xsiny2+C\int \sec(xy)dx+\int \sin{y^2}dx={\frac 1 y}\log(\sec(xy)+\tan(xy))+x\sin{y^2}+C


reference for secant integral formula: https://ocw.mit.edu/courses/mathematics/18-01sc-single-variable-calculus-fall-2010/unit-4-techniques-of-integration/part-a-trigonometric-powers-trigonometric-substitution-and-completing-the-square/session-71-integrals-involving-secant-cosecant-and-cotangent/MIT18_01SCF10_Ses71c.pdf

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Comments

Assignment Expert
14.04.20, 14:43

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Nimra
14.04.20, 02:46

Thank you so much☺️

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