Question

∫ (secx)dx + ∫ (cosxy) dx

Answer 1

$\int(secx)dx+\int(cosxy)dx=$

$=\int(secx)*(secx+tanx)/(secx+tanx)dx+1/y\int(cosxy)dxy=$

$=\int1/(secx+tanx)d(secx+tanx)+(sin(xy))/y=$

$=ln(sec x + tan x)+(sin(xy))/y+C$