Question #108096

∫ x*sinx dx


1
Expert's answer
2020-04-08T05:16:18-0400

We use integration by parts method.

Let u = x, which implies du/dx = 1

and let dv/dx = sin(x). Integrating this to get v gives v = –cos(x).

xsin(x)dx=u(dv/dx)dx=uvv(du/dx)dx=xcos(x)cos(x)1dx=xcos(x)cos(x)dx=xcos(x)+cos(x)dx=xcos(x)+sin(x)+c.∫ x sin(x) dx = ∫ u(dv/dx) dx = uv – ∫ v(du/dx) dx = –x cos(x) – ∫ –cos(x)*1 dx = –x cos(x) – ∫ –cos(x) dx = –x cos(x) + ∫ cos(x) dx = –x cos(x) + sin(x) + c.


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