f′(x)= a +ln(bx)+1, based on a>0, b>1, and x>1 f'(x) always will be greater than 0, so f(x) is increasing
f′′(x)= 1/x, based on a>0, b>1, and x>1 f''(x) always will be greater than 0, so f(x) is concave up
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