Answer to Question #104894 in Calculus for Nimra

Question #104894

f¹₃ (⨯)=cotx4.siny²x³

Expert's answer

"f_x=-\\frac{4x^3}{\\sin^2x^4}\\sin(y^2x^3)+3x^2y^2\\cos(y^2x^3)\\cot x^4"

"f_y=2yx^3\\cos(y^2x^3)\\cot x^4"

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