Find the vector "y\\overrightarrow{b}":
"y\\overrightarrow{b}=y\\overrightarrow{i}+2y\\overrightarrow{j}+y\\overrightarrow{k}"
Tnen
"\\overrightarrow{a}+y\\overrightarrow{b}=(2\\overrightarrow{i}+2\\overrightarrow{j}+3\\overrightarrow{k})+(y\\overrightarrow{i}+2y\\overrightarrow{j}+y\\overrightarrow{k})""\\overrightarrow{a}+y\\overrightarrow{b}=(2+y)\\overrightarrow{i}+(2+2y)\\overrightarrow{j}+(3+y)\\overrightarrow{k}" If "\\overrightarrow{a}+y\\overrightarrow{b}" is perpendicular to "\\overrightarrow{c}" , then their dot product is equal to zero:
"(2+y)\\cdot 3+(2+2y)\\cdot 1+(3+y)\\cdot 0=0" Simplify:
"6+3y+2+2y=0""5y+8=0""y=-\\frac{8}{5}""y=-1.6" Answer: -1.6
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