Question #97564

Vector a= 2i+2j+3k
Vector b=i+2j+k
Vector c= 3i+j
Are such that a+yb is perpendicular to c find y.

Expert's answer

Find the vector yb→y\overrightarrow{b}:


yb→=yi→+2yj→+yk→y\overrightarrow{b}=y\overrightarrow{i}+2y\overrightarrow{j}+y\overrightarrow{k}

Tnen


a→+yb→=(2i→+2j→+3k→)+(yi→+2yj→+yk→)\overrightarrow{a}+y\overrightarrow{b}=(2\overrightarrow{i}+2\overrightarrow{j}+3\overrightarrow{k})+(y\overrightarrow{i}+2y\overrightarrow{j}+y\overrightarrow{k})a→+yb→=(2+y)i→+(2+2y)j→+(3+y)k→\overrightarrow{a}+y\overrightarrow{b}=(2+y)\overrightarrow{i}+(2+2y)\overrightarrow{j}+(3+y)\overrightarrow{k}

If a→+yb→\overrightarrow{a}+y\overrightarrow{b} is perpendicular to c→\overrightarrow{c} , then their dot product is equal to zero:


(2+y)⋅3+(2+2y)⋅1+(3+y)⋅0=0(2+y)\cdot 3+(2+2y)\cdot 1+(3+y)\cdot 0=0

Simplify:


6+3y+2+2y=06+3y+2+2y=05y+8=05y+8=0y=−85y=-\frac{8}{5}y=−1.6y=-1.6

Answer: -1.6


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