Question #96577
line segment AC has endpoints A (-1, -3.5) and C (5,-1). Point B is on like segment AC and is located at (0.2, -3). what is the ratio of AB/BC?
1
Expert's answer
2019-10-16T10:47:10-0400

Point B lies on the line segment AC. Let it divide the line segment in the ratio, k:1k:1 , thus

AB/BC=kAB/BC=k

Using the formula, coordinates of B=(x,y)B=(x,y) are given by

(x,y)=((kx2+x1)/(k+1),(ky2+y1)/(k+1))(x,y)=((kx₂ + x₁)/(k+1), (ky₂ + y₁)/(k+1))

where

A=(x1,y1)=(1,3.5)A=(x₁, y₁)=(-1,-3.5) ;

C=(x2,y2)=(5,1)C=(x₂, y₂)=(5,-1)

Given : B=(x,y)=(0.2,3)B=(x,y)=(0.2,-3)

Solving the x-coordinate for k; we get;

0.2=(k5+(1))/(k+1)0.2=(k*5 +(-1))/(k+1)

=(5k1)/(k+1)=(5k-1)/(k+1)

    k+1=25k5\implies k+1=25k-5

    24k=6\implies 24k=6

k=1/4\therefore k=1/4

AB/BC=0.25 (Answer)

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