Question #96501
Find the work done in moving an object along a vector r=3i+2j-5k, if the applied force is F=2i-j-k
1
Expert's answer
2019-10-14T12:49:01-0400

The work is equivalent to the dot product of the two vectors:

W=rF=(3i+2j5k)(2ijk)==32+2(1)+(5)(1)=9.W=rF=(3i+2j-5k)(2i-j-k)=\\=3*2+2*(-1)+(-5)*(-1)=9.


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