2019-10-16T01:56:57-04:00
Show that for any three vector a, b, c
a*(b*c)+b*(c*a) +c*(a*b) =0
1
2019-10-17T11:24:46-0400
We have:
a × ( b × c ) = b ( a ⋅ c ) − c ( a ⋅ b ) \bold{a\times(b\times c)=b(a\cdot c)-c(a\cdot b)} a × ( b × c ) = b ( a ⋅ c ) − c ( a ⋅ b )
b × ( c × a ) = c ( b ⋅ a ) − a ( b ⋅ c ) \bold{b\times(c\times a)=c(b\cdot a)-a(b\cdot c)} b × ( c × a ) = c ( b ⋅ a ) − a ( b ⋅ c )
c × ( a × b ) = a ( c ⋅ b ) − b ( c ⋅ a ) \bold{c\times(a\times b)=a(c\cdot b)-b(c\cdot a)} c × ( a × b ) = a ( c ⋅ b ) − b ( c ⋅ a ) And
( a ⋅ c ) = ( c ⋅ a ) , ( a ⋅ b ) = ( b ⋅ a ) , ( b ⋅ c ) = ( c ⋅ b ) \bold{(a\cdot c)=(c\cdot a), (a\cdot b)=(b\cdot a), (b\cdot c)=(c\cdot b)} ( a ⋅ c ) = ( c ⋅ a ) , ( a ⋅ b ) = ( b ⋅ a ) , ( b ⋅ c ) = ( c ⋅ b )
Thus,
a × ( b × c ) + b × ( c × a ) + c × ( a × b ) = 0 \bold{a\times(b\times c)+b\times(c\times a)+c\times(a\times b)=0} a × ( b × c ) + b × ( c × a ) + c × ( a × b ) = 0
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