
Please refer to link:
https://en.wikipedia.org/wiki/Conic_section#General_Cartesian_form
General Cartesian form of the equation is:
Ax2+Bxy+Cy2+Dx+Ey+F=0;
If discriminant is equal to zero, the equation represents a parabola.
B2−4AC=22−4×1×1=0.
Therefore it is a parabola.
Figure: parabola.
Comments
The conic also may be traced with a help of a special software (see https://www.math.fsu.edu/~bellenot/class/s10/cla/other/qform.pdf).
There are different ways to find the canonical equation in a new coordinate system. For example, using eigenvalues (hints can be found at https://www.sangakoo.com/en/unit/reduced-and-canonical-equations-of-the-conics) or using a substitution x=Xcos(t)-Ysin(t),, y=Xsin(t)+Ycos(t) (hints can be found at Example 3, https://www.cengage.com/resource_uploads/downloads/1285060288_382318.pdf).
here is just identification ..where is tracing steps