I don't see equation of the hyperbola in the question. So, I present general way and you can substitute any numbers.
This is standard form of the equation of a hyperbola with center (h,k) is
a2(x−h)2−b2(y−k)2=1.The vertices are (−a,0),(a,0).
To find the foci, we need the distance from the center to the foci c2=a2+b2.
The foci are (−c,0),(c,0).
The asymptotes are
a2(x−h)2−b2(y−k)2=0⇒y=±ab(x−h)+k.
Comments
Dear ANJU. Please use the panel for submitting new questions.
Find the vertices,eccentricity,foc and asymptotes of the hyperbola x^2/8-y^2/4=1.Also trace it.Under what condition on ⋋ the line x+⋋y=2 will be tangent to this hyperbola?explain geometrically
Dear Sandeep, The initial equation of a hyperbola was not correctly posted, hence we do not know exactly the actual problem. In our answer we explained how this problem can be solved in a general way.
Sir please send today
please send me this question answer today
Leave a comment