I don't see equation of the hyperbola in the question. So, I present general way and you can substitute any numbers.
This is standard form of the equation of a hyperbola with center "(h,k)" is
"\\dfrac{(x-h)^2}{a^2}-\\dfrac{(y-k)^2}{b^2}=1."The vertices are "(-a,0), \\,\\, (a,0)".
To find the foci, we need the distance from the center to the foci "c^2=a^2+b^2".
The foci are "(-c,0), (c,0)".
The asymptotes are
"\\dfrac{(x-h)^2}{a^2}-\\dfrac{(y-k)^2}{b^2}=0 \\Rightarrow y=\\pm \\dfrac{b}{a}(x-h)+k."
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Dear ANJU. Please use the panel for submitting new questions.
Find the vertices,eccentricity,foc and asymptotes of the hyperbola x^2/8-y^2/4=1.Also trace it.Under what condition on ⋋ the line x+⋋y=2 will be tangent to this hyperbola?explain geometrically
Dear Sandeep, The initial equation of a hyperbola was not correctly posted, hence we do not know exactly the actual problem. In our answer we explained how this problem can be solved in a general way.
Sir please send today
please send me this question answer today
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