Answer to Question #86158 in Analytic Geometry for hitendra

Question #86158
Find the vertices, eccentricity, foci and asymptotes of the hyperbola x2
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Expert's answer
2019-03-11T12:31:03-0400

I don't see equation of the hyperbola in the question. So, I present general way and you can substitute any numbers.

This is standard form of the equation of a hyperbola with center (h,k)(h,k) is

(xh)2a2(yk)2b2=1.\dfrac{(x-h)^2}{a^2}-\dfrac{(y-k)^2}{b^2}=1.

The vertices are (a,0),  (a,0)(-a,0), \,\, (a,0).

To find the foci, we need the distance from the center to the foci c2=a2+b2c^2=a^2+b^2.

The foci are (c,0),(c,0)(-c,0), (c,0).

The asymptotes are

(xh)2a2(yk)2b2=0y=±ba(xh)+k.\dfrac{(x-h)^2}{a^2}-\dfrac{(y-k)^2}{b^2}=0 \Rightarrow y=\pm \dfrac{b}{a}(x-h)+k.


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Comments

Assignment Expert
24.03.19, 15:43

Dear ANJU. Please use the panel for submitting new questions.

ANJU
22.03.19, 22:42

Find the vertices,eccentricity,foc and asymptotes of the hyperbola x^2/8-y^2/4=1.Also trace it.Under what condition on ⋋ the line x+⋋y=2 will be tangent to this hyperbola?explain geometrically

Assignment Expert
22.03.19, 11:12

Dear Sandeep, The initial equation of a hyperbola was not correctly posted, hence we do not know exactly the actual problem. In our answer we explained how this problem can be solved in a general way.

Sandeep
22.03.19, 08:25

Sir please send today

Sandeep
22.03.19, 08:19

please send me this question answer today

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