Question #86158

Find the vertices, eccentricity, foci and asymptotes of the hyperbola x2
8

Expert's answer

I don't see equation of the hyperbola in the question. So, I present general way and you can substitute any numbers.

This is standard form of the equation of a hyperbola with center (h,k)(h,k) is

(xh)2a2(yk)2b2=1.\dfrac{(x-h)^2}{a^2}-\dfrac{(y-k)^2}{b^2}=1.

The vertices are (a,0),(a,0)(-a,0), \,\, (a,0).

To find the foci, we need the distance from the center to the foci c2=a2+b2c^2=a^2+b^2.

The foci are (c,0),(c,0)(-c,0), (c,0).

The asymptotes are

(xh)2a2(yk)2b2=0y=±ba(xh)+k.\dfrac{(x-h)^2}{a^2}-\dfrac{(y-k)^2}{b^2}=0 \Rightarrow y=\pm \dfrac{b}{a}(x-h)+k.


Need a fast expert's response?

Submit order

and get a quick answer at the best price

for any assignment or question with DETAILED EXPLANATIONS!

LATEST TUTORIALS
APPROVED BY CLIENTS