The equation of the sphere with centre (1,3,5) and radius 8 in R3 is
(x−1)2+(y−3)2+(z−5)2=82(x−1)2≥0,x∈R
(y−3)2≥0,y∈R
(z−5)2≥0,z∈R
Then
0≤(x−1)2≤82∣x−1∣≤80≤(y−3)2≤82∣y−3∣≤80≤(z−5)2≤82∣z−5∣≤8Hence
∣x−1∣<10,∣y−3∣<10,∣z−5∣<10,x,y,z∈R
This means that the closed sphere with centre (1,3,5) and radius 8 in R3 is contained in the open cube
P={(x,y,z):∣x−1∣<10,∣y−3∣<10,∣z−5∣<10}.
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