Find the equation of the right circular cone whose vertex is (2, 1, 0), semivertical angle is 30° and the axis is the line x-2/3=y-1/1=z/2
Direction ratio of generator is ( (x - 2), (y - 1), z).
Direction ratio of axis is (3, 1, 2).
Semi vertical angle is 30°.
cos(30°)=(a1a2+b1b2+c1c2)(a12+b12+c12.a22+b22+c22)cos (30°)=\dfrac{(a_1a_2+b_1b_2+c_1c_2)}{(\sqrt{a_1^{2}+b_1^{2}+c_1^{2}}.\sqrt{a_2^{2}+b_2^{2}+c_2^{2}})}cos(30°)=(a12+b12+c12.a22+b22+c22)(a1a2+b1b2+c1c2)
32=(3x+y+2z−7)(14.(x−2)2+(y−1)2+z2\dfrac{\sqrt{3}}{2}=\dfrac{(3x+y+2z-7)}{(\sqrt{14}.\sqrt{(x-2)^{2}+(y-1)^{2}+z^{2}}}23=(14.(x−2)2+(y−1)2+z2(3x+y+2z−7)
42[(x−2)2+(y−1)2+z2]=4[(3x+y+2z−7)2]42[(x-2)^{2}+(y-1)^2+z^{2}]=4[(3x+y+2z-7)^2]42[(x−2)2+(y−1)2+z2]=4[(3x+y+2z−7)2]
6x2+38y2+16z2−24xy−16yz−48xz−28y+112z+14=06x^2+38y^2+16z^2-24xy-16yz-48xz-28y+112z+14=06x2+38y2+16z2−24xy−16yz−48xz−28y+112z+14=0 is the equation of the cone.
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