Answer to Question #217353 in Analytic Geometry for Takam Praise

Question

The set of points M of the plane such that MA²-MB²=0 is?

A. The point I mil[AB]

B. The circle of the center I and radius [AB]

C. The null set

Answer 1

$$MA^2-MB^2=0$$

$$(MA-MB)(MA+MB)=0$$

$$MA-MB=0$$

Perpendicular Bisector is a line or a segment perpendicular to a segment AB that passes through the midpoint of the segment AB.

Any point on the perpendicular bisector is equidistant from the endpoints of the line segment.

The set of points M of the plane such that MA²-MB²=0 is a Perpendicular Bisector to segment AB.

A. The point I mil[AB]