Question

In a cartesian plane xy.The line which passes through the origin and is perpendicular to the line of equation 5x-3y-1=0 has for equation?

A. 3x-5x=0

B. 3x+5y=0

C. 5x-3y=0

Answer 1

Slope of the line 5x-3y-1=0 is $m=\frac{5}{3}.$

Slope of the perpendicular line must be $-\frac{1}{m}=-\frac{3}{5}.$

B. 3x+5y=0.