Calculate the work done by a Force of 2π β π β 3π in moving an object from (2, 1, 3) to (9, 4, 6) where displacement is in meters
"Let\\space the\\space the\\space object\\space move\\space from\\space P(2,\\space 1,\\space 3)\\space to\\space Q(9,\\space 4,\\space 6)\\space \\\\\nHere,\\space the\\space position\\space vectors,\\space \\space \\\\\np\u200b=2 {i} \\space +1 {j} +3 {k} \\\\\nand\\space \\space \\\\\nq\u200b=9 {i} \\space +4 {j} +6 {k} \\\\\nHence,\\space \\space \\\\\nPQ\u200b\\space =\\space q\u200b\\space \u2212\\space p\u200b\t\\space \\\\\n=(9 {i} \\space +4 {j} +6 {k} )\u2212(2 {i} \\space +1 {j} +3 {k} )\\\\\n=7 {i} \\space +3 {j} +3 {k} \\\\\n\\space F\\space =2 {i} \\space -1 {j} -3 {k} \\\\\n\\space \n\u2234\\space Work\\space done\\space =\\space F\\space .\\space PQ\u200b\\\\\n\t\\space \\space =(2 {i} \\space -1 {j} -3 {k} \\space ).(7 {i} \\space +3 {j} +3 {k} )\\\\\n=14-3-9=2\\space meters\\\\"
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