Question #203441

Calculate the work done by a Force of 2š‘– āˆ’ š‘— āˆ’ 3š‘˜ in moving an object from (2, 1, 3) to (9, 4, 6) where displacement is in meters


Expert's answer

Let the the object move from P(2, 1, 3) to Q(9, 4, 6) Here, the position vectors,  p​=2i +1j+3kand  q​=9i +4j+6kHence,  PQ​ = q​ āˆ’ p​ =(9i +4j+6k)āˆ’(2i +1j+3k)=7i +3j+3k F =2i āˆ’1jāˆ’3k āˆ“ Work done = F . PQ​  =(2i āˆ’1jāˆ’3k ).(7i +3j+3k)=14āˆ’3āˆ’9=2 metersLet\space the\space the\space object\space move\space from\space P(2,\space 1,\space 3)\space to\space Q(9,\space 4,\space 6)\space \\ Here,\space the\space position\space vectors,\space \space \\ p​=2 {i} \space +1 {j} +3 {k} \\ and\space \space \\ q​=9 {i} \space +4 {j} +6 {k} \\ Hence,\space \space \\ PQ​\space =\space q​\space āˆ’\space p​ \space \\ =(9 {i} \space +4 {j} +6 {k} )āˆ’(2 {i} \space +1 {j} +3 {k} )\\ =7 {i} \space +3 {j} +3 {k} \\ \space F\space =2 {i} \space -1 {j} -3 {k} \\ \space ∓\space Work\space done\space =\space F\space .\space PQ​\\ \space \space =(2 {i} \space -1 {j} -3 {k} \space ).(7 {i} \space +3 {j} +3 {k} )\\ =14-3-9=2\space meters\\


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