Answer to Question #144128 in Analytic Geometry for sasai

Question #144128
what is the lenght of the conjugate axis?
(x-1)^2/25 -(y+3)^2/9=1
1
Expert's answer
2020-11-15T18:04:59-0500

(x1)225(y+3)29=1\frac{(x-1)^2}{25}- \frac{(y+3)^2}{9}=1 ........ (1)

The standard equation of the hyperbola is given by:

(xh)2a2(yk)2)b2=1\frac{(x-h)^2}{a^2}-\frac{(y-k)^2)}{b^2}=1

When we compare the standard equations and equation (1) we obtain

a2=25a^2= 25 and b2=9b^2=9

This implies that a=5a=5 and b=3b=3

Conjugate axis=2b=2b

=2×3=6=2 \times 3=6 units



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