25(x−1)2−9(y+3)2=1 ........ (1)
The standard equation of the hyperbola is given by:
a2(x−h)2−b2(y−k)2)=1
When we compare the standard equations and equation (1) we obtain
a2=25 and b2=9
This implies that a=5 and b=3
Conjugate axis=2b
=2×3=6 units
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