y=mx+c
-7x+3y=31.5
3y= -31.5+7x
y= 7/3x -43/6
Here m= 7/3
We know that the line passing through AB is perpendicular to the line passing through PQ from the full question
m1 = -1/m2
m2 = slope of PQ = -1/(7/3) = -3/7
y-y1 = m(x-x1)
y-6 = -3/7(x-7)
7y-42= -3x + 21
7y+3x = 21+42
7y +3x = 63
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