AB = 800 ft , AC=BD= 100 ft , HK - ?
cabels have equation y=kx2y=kx^2y=kx2
D(400, 100) belongs to the graph y=kx2y=kx^2y=kx2
100=k∗4002100 = k*400^2100=k∗4002
k=1/1600k = 1/1600k=1/1600
y=1/1600∗x2y = 1/1600 *x^2y=1/1600∗x2
H(200, a) when a=1/1600∗2002=40000/1600=25a = 1/1600*200^2 = 40000/1600 = 25a=1/1600∗2002=40000/1600=25
HK = 25 ft
answer : 25 ft
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