Question #111956
Write an equation for the set of all points in the plane equidistant from (0, – 1) and y= – 5. Write your answer in vertex form. Simplify any fractions
1
Expert's answer
2020-04-27T17:40:45-0400

Let a point P = (x,y)(x, y) .

Given,

A = (0, -1) and

Equation of a line is  y+5=0\space y + 5 =0


PA = (x2x1)2+(y2y1)2=(0x)2+(1y)2\sqrt {(x_2-x_1)^2 + (y_2 -y_1)^2} = \sqrt {(0-x)^2 + (-1-y)^2}


PA = x2+y2+2y+1\sqrt {x^2 + y^2 + 2y+ 1}


Perpendicular Distance from the point (x,y)(x,y) to the Line L: y+5=0y +5 = 0


PL = x(0)+y(1)+50+1=y+5|\frac{x(0) +y(1) +5}{\sqrt {0+1}} | = |{y+5}|


Given, PA = PL



PA2=PL2PA^2 = PL^2

x2+y2+2y+1=(y+5)2x^2+y^2 +2y +1 = (y+5)^2

x2+y2+2y+1=y2+10y+25x^2 +y^2 + 2y +1 = y^2 +10y + 25

x2=8y+24x^2 = 8y+24

x2=8(y+3)x^2 = 8 (y +3)

The equation of set of points in vertex form is, x2=8(y+3)x^2 = 8(y+3)


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