If log𝑎 𝑞 = 1/5 solve the equation , 𝑥 log𝑎 𝑞 + (𝑥 + 2) log𝑎 𝑞2 = 3
Given: log𝑎 𝑞 = 1/5 ...(1)
Now, 𝑥 log𝑎 𝑞 + (𝑥 + 2) log𝑎 𝑞2 = 3
⇒\Rightarrow⇒ 𝑥 log𝑎 𝑞 + (𝑥 + 2).(2 log𝑎 q) = 3 [∵logam=m.loga\because log a^m = m. log a∵logam=m.loga ]
⇒\Rightarrow⇒ x5+(x+2)×2×15=3\frac{x}{5}+(x+2)\times2\times \frac 1 5=35x+(x+2)×2×51=3 [From eq. (1)]
⇒x+2x+4=15⇒3x=11⇒x=113\Rightarrow x+2x+4=15\\ \Rightarrow 3x=11 \\\Rightarrow x =\frac {11}{3}⇒x+2x+4=15⇒3x=11⇒x=311
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