Answer to Question #261187 in Algebra for Master J

Question #261187

If logπ‘Ž π‘ž = 1/5 solve the equation , π‘₯ logπ‘Ž π‘ž + (π‘₯ + 2) logπ‘Ž π‘ž2 = 3


1
Expert's answer
2021-11-09T01:03:18-0500

Given: logπ‘ŽΒ π‘ž = 1/5 ...(1)

Now, π‘₯ logπ‘ŽΒ π‘ž + (π‘₯ + 2) logπ‘ŽΒ π‘ž2Β = 3Β 

"\\Rightarrow"Β π‘₯ logπ‘ŽΒ π‘ž + (π‘₯ + 2).(2 logπ‘ŽΒ q)Β = 3 ["\\because log a^m = m. log a"Β ]

"\\Rightarrow"Β Β "\\frac{x}{5}+(x+2)\\times2\\times \\frac 1 5=3"Β [From eq. (1)]

"\\Rightarrow x+2x+4=15\\\\\n\\Rightarrow 3x=11\n\\\\\\Rightarrow x =\\frac {11}{3}"

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