Question #261187

If logπ‘Ž π‘ž = 1/5 solve the equation , π‘₯ logπ‘Ž π‘ž + (π‘₯ + 2) logπ‘Ž π‘ž2 = 3


Expert's answer

Given: logπ‘Ž π‘ž = 1/5 ...(1)

Now, π‘₯ logπ‘Ž π‘ž + (π‘₯ + 2) logπ‘Ž π‘ž= 3 

β‡’\Rightarrow π‘₯ logπ‘Ž π‘ž + (π‘₯ + 2).(2 logπ‘Ž q) = 3 [∡logam=m.loga\because log a^m = m. log a ]

β‡’\Rightarrow  x5+(x+2)Γ—2Γ—15=3\frac{x}{5}+(x+2)\times2\times \frac 1 5=3 [From eq. (1)]

β‡’x+2x+4=15β‡’3x=11β‡’x=113\Rightarrow x+2x+4=15\\ \Rightarrow 3x=11 \\\Rightarrow x =\frac {11}{3}

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