Question #261187

If log𝑎 𝑞 = 1/5 solve the equation , 𝑥 log𝑎 𝑞 + (𝑥 + 2) log𝑎 𝑞2 = 3


1
Expert's answer
2021-11-09T01:03:18-0500

Given: log𝑎 𝑞 = 1/5 ...(1)

Now, 𝑥 log𝑎 𝑞 + (𝑥 + 2) log𝑎 𝑞= 3 

\Rightarrow 𝑥 log𝑎 𝑞 + (𝑥 + 2).(2 log𝑎 q) = 3 [logam=m.loga\because log a^m = m. log a ]

\Rightarrow  x5+(x+2)×2×15=3\frac{x}{5}+(x+2)\times2\times \frac 1 5=3 [From eq. (1)]

x+2x+4=153x=11x=113\Rightarrow x+2x+4=15\\ \Rightarrow 3x=11 \\\Rightarrow x =\frac {11}{3}

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