Given that π = 3β 32π4βπ /2 . Show that π = 1/2 4β2π3 + π Β Β
"\ud835\udc47 = \\frac{\\sqrt[3]{32\ud835\udc50^4\u2212\ud835\udc5e }}{2}"
"2\u00d7T=\\sqrt[3]{32\ud835\udc50^4-q}"
"2^3\u00d7T^3={32\ud835\udc50^4-q}"
"8T^3={32\ud835\udc50^4-q}"
"8T^3+q={32\ud835\udc50^4}"
"\\sqrt[4]\\frac{8T^3+q}{32}={\ud835\udc50}"
"c=\\frac{1}{2}\\sqrt[4]{2T^3+q}"
Comments
Leave a comment