Given that ð = 3â 32ð4âð /2 . Show that ð = 1/2 4â2ð3 + ð
ð=32ð4âð32ð = \frac{\sqrt[3]{32ð^4âð }}{2}T=2332c4âqââ
2ÃT=32ð4âq32ÃT=\sqrt[3]{32ð^4-q}2ÃT=332c4âqâ
23ÃT3=32ð4âq2^3ÃT^3={32ð^4-q}23ÃT3=32c4âq
8T3=32ð4âq8T^3={32ð^4-q}8T3=32c4âq
8T3+q=32ð48T^3+q={32ð^4}8T3+q=32c4
\sqrt[4]\frac{8T^3+q}{32}={ð}
c=122T3+q4c=\frac{1}{2}\sqrt[4]{2T^3+q}c=21â42T3+qâ
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