Answer to Question #261008 in Algebra for Master J

Question #261008

If logπ‘Ž π‘ž = 1/5 solve the equation , π‘₯ logπ‘Ž π‘ž + (π‘₯ + 2) logπ‘Ž π‘ž2 = 3Β 


1
Expert's answer
2021-11-05T10:07:13-0400

Given: logπ‘ŽΒ π‘ž = 1/5 ...(1)

Now, π‘₯ logπ‘ŽΒ π‘ž + (π‘₯ + 2) logπ‘ŽΒ π‘ž2Β = 3Β 

"\\Rightarrow" π‘₯ logπ‘ŽΒ π‘ž + (π‘₯ + 2).(2 logπ‘ŽΒ q)Β = 3 ["\\because log a^m = m. log a" ]

"\\Rightarrow" Β "\\frac{x}{5}+(x+2)\\times2\\times \\frac 1 5=3" [From eq. (1)]

"\\Rightarrow x+2x+4=15\\\\\n\\Rightarrow 3x=11\n\\\\\\Rightarrow x =\\frac {11}{3}"


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