Question #79207
The heat transfer from a 2 m diameter sphere to a 25 °C air stream over a time interval of one hour is 3000 kJ. Estimate the surface temperature of the sphere if the heat transfer coefficient is 10 W/m²K
Answer:
The convective heat transfer (Q=3000 kJ=3000000 J) is given by:
Q=hA(Tw−Tf)τ,
where h=10 W/m2K is the heat transfer coefficient,
A=πd2
is the surface area of the sphere,
d=2 m is the diameter of the sphere,
Tw is the surface temperature,
Tf=25∘C is the temperature of the air,
τ=1 hr=3600 s is the period of time.
So, we can derive Tw from (1) as follows:
Tw=Tf+hAτQ,
Substitute into (2) and (3):
A=π⋅22=12.566 m2,Tw=25+10⋅12.566⋅36003000000=31.6∘C.