state−1
p1=2mpa
t1=3750c
h1=3137.7+(400−350)(3248.4−3137.7)×(375−350)=3193.05kgkj
s1=6.9583+(400−350)(7.1292−6.9583)×(375−350)=7.0437kg,kkj
state−2
T2=950C
S2=S1=7.0437kg,kkj
Sf2=1.2504
Sg2=7.4151
hf2=398.09
hfg2=2269.6
The dryness factor ,x2=sg2−sf2s2−sf2=0.9397
h2=hf2+x2hfg2=2530.83kgkj
energy balance for steady flow process
Ein−Eout=△energy
h1−Wout−h2=0
Wout=h1−h2=3193.05−2530.83=662.22
The non-flow process:
Q=△U+W
W=−△U=−u2−u1
u1=2860.5+(400−350)(2945.9−2860.5)×(375−350)=2903.2kgkJ
u2=398+(0.9397)(2102)=2373.25kgkJ
w=2903.2−2373.25=529.95kgkJ
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