*Problem1*
f(x) = log((1-|x|)÷(1+|x|))
•It's largest domain
•It's intersections with the x-axis (if any)
•It's intersection with the y-axis (if any)
•It's sign
•when appropriate, end behaviours and behaviours at accumulation points of the domain which are not in the domain, possible asymptotes.
*Problem 2*
Compute, showing the procedure,
limit from x to positive infinity of the problem encircled in brackets ( square root symbol x^2-3x - square root symbolx^2-5x+1)
*Problem 3*
Compute, showing the procedure,
limit from x to negative infinity of the expresion: (square root symbol x^6-x^2)÷(1-2x)
Problem-1
for the finding linear equation of the function "f(x) = log((1-|x|)\u00f7(1+|x|))" it will be the intersection with the Y-axis.
so the option c) intersection with y-axis is accurate
problem-2
procedure/principal
The ones function creates a matrix whose elements are all ones. Typing ones(m,n) creates an m row by n column matrix of ones. To create a ones matrix that is the same size as an existing matric, you can use ones(size(X)). This does not affect the input argument. For example (this definition of x applies to subsequent examples in this section)
problem-3
Indexing:
If x is already defined as a vector of the form [val1 val2 val3 val4...] then you can define a new variable as a subset of xby using the index of the specific value in vector x. For example, if x is defined as [2 4 1 7], then:
>> z = x(3)
This means that the first element always has index (1,1), not (0,0).
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