The natural frequency of vibration, in bending, of the wing of a military aircraft is found to be 20 Hz. Find the new frequency of bending vibration of the wing when a weapon, weighing 2000 lb, is attached at the tip of the wing, as shown in Figure. The stiffness of the wing tip, in bending, is known to be 50,000 lb/ft.
The natural frequency of the wing itself is "\\omega_{11}=20 Hz =(20 *2 \\pi)=125.664 rad\/s"
The natural frequency of the weapon "\\omega _{22}=\\sqrt{\\frac{k}{m}}=\\sqrt{\\frac{50000*386.4}{12*2000}}=28.3725 rad\/s"
The frequency of vibration of the wing with weapon
"\\frac{1}{\\omega _1^2}=\\frac{1}{\\omega _{11}^2}+\\frac{1}{\\omega _{22}^2}"
"\\frac{1}{\\omega _1^2}=\\frac{1}{125.664^2}+\\frac{1}{28.3725^2}"
"\\omega _1=\\frac{\\sqrt{\\frac{1}{130.5563*10^{5}}}}{2\\pi}=\\frac{27.6759}{2*3.14}=4.4047 Hz"
Comments
Leave a comment