Answer to Question #193737 in Mechanical Engineering for Lemony

Question #193737

The natural frequency of vibration, in bending, of the wing of a military aircraft is found to be 20 Hz. Find the new frequency of bending vibration of the wing when a weapon, weighing 2000 lb, is attached at the tip of the wing, as shown in Figure. The stiffness of the wing tip, in bending, is known to be 50,000 lb/ft.


1
Expert's answer
2021-05-20T12:44:02-0400

The natural frequency of the wing itself is ω11=20Hz=(202π)=125.664rad/s\omega_{11}=20 Hz =(20 *2 \pi)=125.664 rad/s

The natural frequency of the weapon ω22=km=50000386.4122000=28.3725rad/s\omega _{22}=\sqrt{\frac{k}{m}}=\sqrt{\frac{50000*386.4}{12*2000}}=28.3725 rad/s

The frequency of vibration of the wing with weapon

1ω12=1ω112+1ω222\frac{1}{\omega _1^2}=\frac{1}{\omega _{11}^2}+\frac{1}{\omega _{22}^2}

1ω12=1125.6642+128.37252\frac{1}{\omega _1^2}=\frac{1}{125.664^2}+\frac{1}{28.3725^2}

ω1=1130.55631052π=27.675923.14=4.4047Hz\omega _1=\frac{\sqrt{\frac{1}{130.5563*10^{5}}}}{2\pi}=\frac{27.6759}{2*3.14}=4.4047 Hz


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