Design a rigid coupling is used to connect a 45 kW,1440 rpm electric motor to a
centrifugalpump. The starting torque of the motor is225% of the rated torque
power "P = 45KW = 45,000 Nm"
RPM N = 1440
"T = \\frac{P \\times 60}{2\\pi N} = \\frac{45000 \\times 60}{2\\pi 1440} = 298.41 Nm"
As starting torque of the motor is 225% of rated torque.
"T_{max} = 2.25 \\times T = 2.25 \\times 298.41 = 671.42 Nm"
Comments
Leave a comment