A spring extends 3 inches when loaded vertically with 4 lbs. This weight was pulled further down by 3 inches an was released from rest. Determine the frequency of vibration in rad per second
4lbs = 1.81 kgs
3inches = 0.0762 m
k=17.8Newtons0.0762m=233.59N/mk= \frac{17.8Newtons}{ 0.0762m}=233.59N/mk=0.0762m17.8Newtons=233.59N/m
= 237.5328N/m
ωn=km=233.591.81=11.35rad/s\omega_n= \sqrt{\frac{k}{m}}= \sqrt{\frac{233.59}{1.81}}=11.35 rad/sωn=mk=1.81233.59=11.35rad/s
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