Answer to Question #137272 in Mechanical Engineering for lazona ck

Question #137272
A piston cylinder contains gas initially at 3500 kPa with a volume of 0.03 cubic meter. The gas
is compressed during a process where pV raise to 1.25 = C to a pressure of 8500 kPa. The heat
transfer from the gas is 2.5 kJ. neglecting changes in kinetic and potential energies determine the nonflow work in kJ.
1
Expert's answer
2020-10-08T15:10:41-0400

The polytropic process is one in which the pressure-volume relation is given as "pV^n=constant"

"pV^{1.25} =constant\\implies p_1V_1^{1.25}=p_2V_2^{1.25}"

"V_2=V_1(\\frac{p_1}{p_2})^{\\frac{1}{1.25}}=0.03(\\frac{3500}{8500})^{\\frac{1}{1.25}}=0.01475 m^3"

The work done during the polytropic process is found by substituting the pressure volume

relation into the boundary work equation. The result is "W= \\int_1^2pdV=\\frac{p_2V_2-p_1V_1}{1-n}"

"W=\\frac{8500\u00d710^3\u00d70.01475-3500\u00d710^3\u00d70.03}{1-1.25}=-81500 J"

Then, according to the first law of thermodynamics, "\u0394U=Q-W=-2500+81500=79000 J=79kJ"


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