Answer to Question #137243 in Mechanical Engineering for Sibsankar giri

Question #137243
. A 200 × 150 × 10 angle is to be welded to a steel plate by fillet welds as shown in Figure. If
the angle is subjected to a static load of 300kN, find the length of weld at the top & bottom.
The allowable shear stress may be taken as 75 N/mm2
.
1
Expert's answer
2020-10-08T15:10:10-0400

Given static loading =300 kN = 300 "\\times 10^3" N ,here dimension is given as 200 "\\times 150\\times 10" ,

permissible shear stress= 75 "\\frac{kN}{mm^2}" ,here a+b=200


s= size of weld = thickness= 10 ,we know that

for single weld

"300 \\times 10 ^3=0.707 \\times s \\times l\\times \\tau"

on putting value we can get value of l

l= 303.09 mm

"l_a+ l_b=565.77"

now distance of centroidal axis from bottom angle

b=55.3 and a= 144.7 so

"l_a= \\frac{l\\times b}{a+b}"

"l_a=156.44" and "l_b= 366.88"

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