Answer to Question #137243 in Mechanical Engineering for Sibsankar giri

Question

. A 200 × 150 × 10 angle is to be welded to a steel plate by fillet welds as shown in Figure. If
the angle is subjected to a static load of 300kN, find the length of weld at the top & bottom.
The allowable shear stress may be taken as 75 N/mm2
.

Answer 1

Given static loading =300 kN = 300 $\times 10^3$ N ,here dimension is given as 200 $\times 150\times 10$ ,

permissible shear stress= 75 $\frac{kN}{mm^2}$ ,here a+b=200

s= size of weld = thickness= 10 ,we know that

for single weld

$300 \times 10 ^3=0.707 \times s \times l\times \tau$

on putting value we can get value of l

l= 303.09 mm

$l_a+ l_b=565.77$

now distance of centroidal axis from bottom angle

b=55.3 and a= 144.7 so

$l_a= \frac{l\times b}{a+b}$

$l_a=156.44$ and $l_b= 366.88$