Initial pressure(p1)=3500x103 Pa
Initial Volume (V1)=0.03 m3
Final pressure(p2)=8500 x103 Pa
Gas undergoes a polytropic process given by pV1.25=constant
Therefore, for process 1-2 we can write,
p1×V11.25=p2×V21.25
V21.25=p2p1×V11.25 =0.01475 m3
The work done during poly tropic process is given by
W=n−1p1×V1−p2×V2
W=1.25−1(3500×(0.03)−(8500)×(0.01475) =-81.5 kJ (-ve sign indicates work done on the gas)
Work done on the gas is W=81.5 kJ
Comments
Leave a comment