Question #136257

Water enters the heater with 25 degree Celsius and leaves at 78 degree Celsius. The temperature change is Answer degree Fahrenheit.?


1
Expert's answer
2020-10-02T14:50:34-0400

Water enters at T1=25oC,T2=78oCT_1=25^oC,T_2=78^oC is the temperature of leaving the water

Change in temperature= ΔT=T2T1=7825=53oC\Delta T=T_2-T_1=78-25=53 ^oC

So, we know the relation between temperature in degree Celsius and temperature in degree Fahrenheit


T(oF)=95(ToC)+32T(^oF)= \frac{9}{5}(T^oC)+32


T(oF)=95(53)+32T(^oF)= \frac{9}{5}(53)+32


T(oF)=127.4oFT(^oF)=127.4 ^oF




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