Answer to Question #163005 in Chemistry for marwan

Question

what is the concentration of ammonium acetate solution if you dissolve 30.9g in 2 L

Answer 1

Solution:

ammonium acetate - CH₃COONH₄

Moles of CH₃COONH₄ = Mass of CH₃COONH₄ / Molar mass of CH₃COONH₄

The molar mass of ammonium acetate (CH₃COONH₄) is 77.083 g mol^-1.

Hence,

Moles of CH₃COONH₄ = 30.9 g / 77.083 g mol^-1 = 0.40087 mol = 0.4 mol

Molarity of CH₃COONH₄ = Moles of CH₃COONH₄ / Solution volume

Hence,

Molarity of CH₃COONH₄ = 0.4 mol / 2 L = 0.2 mol/L = 0.2 M

Molarity of CH₃COONH₄ = 0.2 M

Answer: The molar concentration (or molarity) of ammonium acetate (CH₃COONH₄) solution is 0.2 M.