The reaction 2A + 3B C is first order with respect to A and B. When the initial concentrations are [A] = 1.6 x 10-2 M and [B] = 2.4 x 10-3 M, the rate is 4.1 x 10-4 M/s. Calculate the rate constant of the reaction. (5 points)
According to the equation:
r = k[A]a[B]b
where r - reaction rate, k - rate constant, [A] and [B] - concentrations of compounds A and B, a and b - order of the reaction.
From here, the rate constant of the reaction is:
k = r / [A]a[B]b = 4.1 × 10-4 M/s / [(1.6 × 10-2 M)1 × (2.4 × 10-3 M)1] = 10.7 M-1 s-1
Answer: 10.7 M-1 s-1
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