Answer to Question #162380 in Chemistry for Ava Brooke

Question

Using the following chemical equation how many grams of calcium chloride are produced when 18.84 g of water are produced?

2HCl + Ca(OH)₂ -> 2H₂O + CaCl₂

Answer 1

Solution:

The balanced chemical equation:

Ca(OH)₂ + 2HCl → CaCl₂ + 2H₂O

According to the equation above: n(CaCl₂) = n(H₂O)/2

Moles of H₂O = Mass of H₂O / Molar mass of H₂O

The molar mass of H₂O is 18.0153 g mol^-1.

Hence,

n(H₂O) = 18.84 g / 18.0153 g mol^-1 = 1.04578 mol

n(CaCl₂) = n(H₂O) / 2 = 1.04578 mol / 2 = 0.52289 mol

Moles of CaCl₂ = Mass of CaCl₂ / Molar mass of CaCl₂

Mass of CaCl₂ = Moles of CaCl₂ × Molar mass of CaCl₂

The molar mass of CaCl₂ is 110.98 g mol^-1.

Hence,

m(CaCl₂) = 0.52289 mol × 110.98 g mol^-1 = 58.0303 g = 58.0 g

Answer: 58.0 grams of calcium chloride (CaCl₂) are produced.