Answer to Question #162385 in Chemistry for Ava Brooke

Question

If 8.77 grams of table salt (NaCl) are dissolved in a total volume of 30 mL of water what is the molarity?

Answer 1

Solution:

Moles of NaCl = Mass of NaCl / Molar mass of NaCl

The molar mass of NaCl is 58.44 g/mol.

Hence,

Moles of NaCl = 8.77 g / 58.44 g mol^-1 = 0.15 mol

Moles of NaCl = 0.15 mol

Convert 30 mL to liters

1 L=1000 mL

30 mL × (1 L / 1000 mL) = 0.03 L

Solution volume = 0.03 L

Molarity of NaCl = Moles of NaCl / Solution volume

Hence,

Molarity of NaCl = 0.15 mol / 0.03 L = 5 mol/L = 5 M

Molarity of NaCl = 5 M

Answer: The molarity of NaCl is 5 M.