Answer to Question #108396 in Chemistry for C

Question

hi,I have completed this but says I made 1 error,may i please ask which 1 is fillied in incorrectly?
-fillied in words are in brackets

1)H2S : ( bent) electron-domain geometry with (2 nonbonding pairs )on S will cause the bond angle to deviate from ideal (109.5)∘

2)BCl3: ( trigonal planar )electron-domain geometry with( 0 nonbonding pairs )on B. We confidently predict (120∘ )angles.

3)CH3I: :( tetrahedral) electron-domain geometry with( 0 nonbonding pairs) on C. Because the bonding electron domains are not exactly the same, we predict some deviation from ideal (109.5)∘ angles.

4)CBr4:( tetrahedral) electron-domain geometry with( 0 nonbonding pairs )on C. We confidently predict (109.5)∘ angles.

5)TeBr4: ( trigonal bipyramidal) electron-domain geometry with (1 nonbonding pair )on Te will cause the bond angles to deviate from ideal values.

Answer 1

Answer: The error should be in (1). There is a difference between the molecular shape and the electron geometry. 'Bent' is the molecular shape of H₂S. Its electron domain geometry is tetrahedral, as central atom S is surrounded by 4 electron domains: 2 non-bonding electron pairs and 2 bonding electron pairs, shared with two hydrogens. The rest is correct: due to the non-equivalence of bonding and non-bonding electron pairs, the bond angle deviates from the ideal 109.5°.