Solution:
HBr is a strong acid in aqueous media therefore it ionizes 100%.
HBr + H2O = H3O+ + Br-
or
HBr = H+ + Br-
This means that
[H3O+] = [H+] = [HBr] = 1.65*10-4 M.
pH = −log[H3O+] = −log[H+].
Therefore,
pH = −log[H3O+] = −log[1.65*10-4] = 3.78
pH = 3.78
Answer: 3.78 is the pH of 1.65*10-4 M solution of HBr.
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