Question

Find the pH of 3.89 x 10-4 M of HCl

Answer 1

Solution:

HCl is a strong acid in aqueous media therefore it ionizes 100%.

HCl = H⁺ + Cl^-

This means that

[H⁺] = [HCl] = 3.89*10^-4 M.

pH = −log[H⁺].

Therefore,

pH = −log[H⁺] = −log[3.89*10^-4] = 3.41

pH = 3.41

Answer: 3.41 is the pH of 3.89*0^-4 M solution of HCl.