Solution:
HClO2 is a weak acid in aqueous media.
Therefore, HClO2 ionizes but less than 100% to produce protons (H+).
The acid dissociation constant for HClO2 is Ka = 1.1*10-2.
Let's set up a reaction table for the following ionization: HClO2 ↔ H+ + ClO2-
Then,
1.1*10-2 * (0.23 - x) = x*x;
x2 + 0.011*x - 0.00253 = 0
Solving this quadratic equation, we get that x = 0.0451
x = [H+] = 0.0451 M.
pH = −log[H+].
Therefore,
pH = −log[H+] = −log[0.0451] = 1.3458 = 1.35
pH = 1.35
Answer: 1.35 is the pH of 0.23 M HClO2.
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