Answer to Question #97733 in General Chemistry for PIja

Question

Bleaching powder, CaOCl2is added to 3.00 mol of hydrochloric acid, HCl to produce calcium chloride, water and chlorine gas.

CaOCl2(s) + 2HCl (aq) ➜ CaCl2 (s)+ H2O (l)+ Cl2 (g)

a)Calculate the mass of calcium chloride formed

b) Determine the volume of chlorine gas obtained at STP. Given that 1 mole of gas occupies 22.4 dm3at STP

Answer 1

When bleaching powder reacts with dil. HCl to liberate Cl2 gas,water and Calcium Chloride . CaOCl2 + 2HCl ----> CaCl2 +Cl2 +H2O. Bleaching powder is calcium oxychloride (CaOCl2), also called as chloride of lime.

a). Mass of chloride form=58.5g

b).The volume of all the gases at stp is 22.4 L .

For different moles of gasea compare the volume 22.4 L