"\\Delta"Hf0 SO2 = -296.84 kJ/mol
"\\Delta" Hf0 SO3 = -395.7 kJ/mol
"\\Delta" Hf0 O2 = 0 kJ/mol
So, the enthalpy change of reaction will be
"\\Delta" Hrxn = [2moles*(-395.7kJ/mol)] - [2moles*(-296.84kJ/mol) + 1mole*0kJ/mol] = -791.4 kJ + 593.68 kJ = -197.7 kJ
2) The products are elements, so the enthalpy change forse them is 0.
For water is -285,8 for one mole, but there are 2:
"\\Delta"Hrxn = 0-(-285,8x2) = +572 kJ
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