Q97596
Solution:
As Enthalpy "\u0394H\u00b0" is an extensive property of a thermodynamic system, it changes with stoichiometric coefficients of the reaction.
Given:
"A + 2B \\to E" "\u0394H\u00b0_1 = 70 kJ" ---(1)
"C + 2D \\to 2E" "\u0394H\u00b0_2 = -25 kJ" ---(2)
"F + 2A \\to D" "\u0394H\u00b0_3 = 60 kJ" ---(3)
To find: "4 B \\to 2 A + C + 2 F" "\u0394H\u00b0=?"
Now, the required chemical equation can be obtained by doing the following;
"2*(1)-(2)-2*(3)"
Thus, the enthalpy of the required chemical reaction becomes "\u0394H\u00b0= 2\u0394H\u00b0_1- \u0394H\u00b0_2-2 \u0394H\u00b0_3"
"\u0394H\u00b0=(2*70)-(-25)-(2*60)"
"=140+25-120"
"=45kJ"
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