Question

1. Methane (CH4) combusts as shown in the equation below. If 3 moles of methane were used in the combustion, what would be the change in enthalpy (H) for the reaction?
CH4(g) + 2 O2(g)  CO2(g) + 2 H2O(g) H = 802 kJ

Answer 1

delta H=-802*3=-2406 kJ

Sorry, this answer is correct