Question #97669
How many grams of NaCl are present in 8.39x10 22 formula units of NaCl
1
Expert's answer
2019-11-01T05:44:35-0400

Moles of NaCl=8.39×10226.023×1023=0.139NaCl=\frac{8.39\times10^{22}}{6.023\times10^{23}}=0.139

Mass of NaCl=0.139×58.5=8.149gNaCl=0.139\times58.5=8.149g


Need a fast expert's response?

Submit order

and get a quick answer at the best price

for any assignment or question with DETAILED EXPLANATIONS!

Place free inquiry
Calculate the price
Learn more about our help with Assignments: Chemistry

Comments

No comments. Be the first!
Our fields of expertise
Submit Your Assignment. We Can Do It.
LATEST TUTORIALS
APPROVED BY CLIENTS
Finding a professional expert in "partial differential equations" in the advanced level is difficult. You can find this expert in "Assignmentexpert.com" with confidence. Exceptional experts! I appreciate your help. God bless you!
Canada #340153 on Dec 2023