Answer to Question #97669 in General Chemistry for JAmes

General Chemistry

Question #97669

How many grams of NaCl are present in 8.39x10 22 formula units of NaCl

Expert's answer

Moles of "NaCl=\\frac{8.39\\times10^{22}}{6.023\\times10^{23}}=0.139"

Mass of "NaCl=0.139\\times58.5=8.149g"

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