CH4(g) + 4Cl2(g) → CCl4(l) + 4HCl(g)
ΔH= ((−139 kJ/mol) + 4 x (−92.31 kJ/mol)) - ((−74.87 kJ/mol) + (121.0 kJ/mol))= (-508.24 kJ/mol) - 46.13 kJ/mol = -554.37 kJ/mol.
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